If the size of the int is that important one can use int16_t, int32_t and int64_t (need the iostream include for that if I remember correctly). What's nice about this that int64_t should not have issues on a 32bit …

The size of char in bits isn't specified explicitly either, although sizeof (char) is defined to be 1. If you want a 64 bit int, C++11 specifies long long to be at least 64 bits.

238 I know it's equal to sizeof(int). The size of an int is really compiler dependent. Back in the day, when processors were 16 bit, an int was 2 bytes. Nowadays, it's most often 4 bytes on a 32-bit as well as …

Sep 1, 2010 · Sizes of C++ objects are expressed in terms of multiples of the size of a char , so by definition the size of a char is 1 . The size of an object or type can be obtained using the sizeof operator

Jan 1, 2015 · Тип size_t обычно применяется для счетчиков циклов, индексации массивов, хранения размеров, адресной арифметики. Так как его размер совпадает с размером …

Feb 25, 2010 · The compiler is free to implement a hardware abstraction layer of any thickness and emulate absolutely anything. There's nothing to prevent a C or C++ implementation from …

And since C++ doesn't have variable-length arrays the dimensions of an array must be known at compile time. The use of const for function arguments is more of a hint to the compiler that the function will …

586 From Wikipedia: According to the 1999 ISO C standard (C99), size_t is an unsigned integer type of at least 16 bit (see sections 7.17 and 7.18.3). size_t is an unsigned data type defined by several …

In several C++ examples I see a use of the type size_t where I would have used a simple int. What's the difference, and why size_t should be better?

Aug 21, 2013 · The standard also requires that: int is at least 16 bits. long int is at least 32 bits and long long int is at least 64 bits. With 32 bit processors being maintstream, compilers typically set int to be …